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← JEE Main 2017 · 8 Apr · Shift 1
PhysicsSingle correct+4 / -1Question 23 of 90

JEE Main 2017 · 8 Apr · Shift 1, Physics question 23

A single slit of width b is illuminated by a coherent monochromatic light of wavelength λ. If the second and fourth minima in the diffraction pattern at a distance 1 m from the slit are at 3 cm and 6 cm respectively from the central maximum, what is the width of the central maximum ? (i.e. distance between first minimum on either side of the central maximum)

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Answer and worked solution

Official answer: B

Minima are at yn=nλDby_n=\dfrac{n\lambda D}b. The second minimum at 3 cm gives λDb=1.5\dfrac{\lambda D}b=1.5 cm (the fourth, at 6 cm, agrees). The central maximum is 2×1.5=3.02\times1.5=3.0 cm wide.