JEE Main 2017 · 8 Apr · Shift 1 · Physics Q16

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PhysicsSingle correct+4 / -1Question 16 of 90

What is the conductivity of a semiconductor sample having electron concentration of $5\times10^{18}$ m $^{-3}$ , hole concentration of $5\times10^{19}$ m $^{-3}$ , electron mobility of 2.0 m $^2$ V $^{-1}$ s $^{-1}$ and hole mobility of 0.01 m $^2$ V $^{-1}$ s $^{-1}$ ?

(Take charge of electron as $1.6\times10^{-19}$ C)

1.68 (Ω-m)

^{-1}

1.83 (Ω-m)

^{-1}

0.59 (Ω-m)

^{-1}

1.20 (Ω-m)

^{-1}

Answer and worked solution

Official answer: A

$\sigma=e(n\mu_e+p\mu_h)=1.6\times10^{-19}(5\times10^{18}\times2+5\times10^{19}\times0.01)=1.6\times10^{-19}\times1.05\times10^{19}=1.68\ (\Omega\text{-m})^{-1}.$

Topics:Semiconductors and p-n junction

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JEE Main 2017 · 8 Apr · Shift 1, Physics question 16