JEE Main 2017 · 8 Apr · Shift 1 · Physics Q1

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Time (T), velocity (C) and angular momentum (h) are chosen as fundamental quantities instead of mass, length and time. In terms of these, the dimensions of mass would be :

[M]=[T^{-1}C^{-2}h]

[M]=[T^{-1}C^2h]

[M]=[T^{-1}C^{-2}h^{-1}]

[M]=[TC^{-2}h]

Answer and worked solution

Official answer: A

$h=[ML^2T^{-1}]$ and $L=CT$ , so
$M=\frac h{L^2T^{-1}}=\frac h{C^2T^2\cdot T^{-1}}=[T^{-1}C^{-2}h].$

Topics:Dimensional analysis

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JEE Main 2017 · 8 Apr · Shift 1, Physics question 1