JEE Main 2017 · 8 Apr · Shift 1 · Mathematics Q67 · Dronacharya Exams

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MathematicsSingle correct+4 / -1Question 67 of 90

If $(27)^{999}$ is divided by 7, then the remainder is :

A

1

B

2

C

3

D

6

Answer and worked solution

Official answer: D

$27\equiv-1\pmod7$ , so $27^{999}\equiv-1\equiv6$ .

Topics:Binomial expansion Number systems

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