JEE Main 2017 · 8 Apr · Shift 1 · Chemistry Q50

← JEE Main 2017 · 8 Apr · Shift 1

ChemistrySingle correct+4 / -1Question 50 of 90

A solution containing a group-IV cation gives a precipitate on passing $\ce{H2S}$ . A solution of this precipitate in dil.HCl produces a white precipitate with NaOH solution and bluish-white precipitate with basic potassium ferrocyanide. The cation is :

\ce{Co^2+}

\ce{Ni^2+}

\ce{Mn^2+}

\ce{Zn^2+}

Answer and worked solution

Official answer: D

Group IV cations precipitate as sulphides in ammoniacal $\ce{H2S}$ . Zinc gives white $\ce{Zn(OH)2}$ with NaOH and bluish-white zinc ferrocyanide with potassium ferrocyanide, so the cation is $\ce{Zn^2+}$ .

Topics:Cation analysis

← Previous question Next question →

JEE Main 2017 · 8 Apr · Shift 1, Chemistry question 50