JEE Main 2017 · 8 Apr · Shift 1 · Chemistry Q43

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ChemistrySingle correct+4 / -1Question 43 of 90

$sp^3d^2$ hybridization is not displayed by :

\ce{BrF5}

\ce{SF6}

\ce{[CrF6]^3-}

\ce{PF5}

Answer and worked solution

Official answer: D

$\ce{PF5}$ has 5 bonding pairs and no lone pair: $sp^3d$ . $\ce{BrF5}$ (5 bonds + 1 lone pair), $\ce{SF6}$ and $\ce{[CrF6]^3-}$ are all $sp^3d^2$ (the last as $d^2sp^3$ is also possible, but it is octahedral either way).

Topics:Hybridisation Valence bond theory

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JEE Main 2017 · 8 Apr · Shift 1, Chemistry question 43