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← JEE Main 2017 · 2 Apr · Shift 1
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JEE Main 2017 · 2 Apr · Shift 1, Physics question 30

The following observations were taken for determining surface tension T of water by capillary method :

diameter of capillary, D=1.25×10−2D=1.25\times10^{-2} m

rise of water, h=1.45×10−2h=1.45\times10^{-2} m.

Using g=9.80g=9.80 m/s2^2 and the simplified relation T=rhg2×103T=\dfrac{rhg}2\times10^3 N/m, the possible error in surface tension is closest to :

Choose one option
Answer and worked solution

Official answer: B

T∝rhgT\propto rhg, so
ΔTT=Δrr+Δhh+Δgg=0.011.25+0.011.45+0.019.80=0.80%+0.69%+0.10%≈1.6%,\frac{\Delta T}T=\frac{\Delta r}r+\frac{\Delta h}h+\frac{\Delta g}g=\frac{0.01}{1.25}+\frac{0.01}{1.45}+\frac{0.01}{9.80}=0.80\%+0.69\%+0.10\%\approx1.6\%,
closest to 1.5%.