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← JEE Main 2017 · 2 Apr · Shift 1
PhysicsSingle correct+4 / -1Question 13 of 90

JEE Main 2017 · 2 Apr · Shift 1, Physics question 13

An observer is moving with half the speed of light towards a stationary microwave source emitting waves at frequency 10 GHz. What is the frequency of the microwave measured by the observer ? (speed of light = 3×1083\times10^8 ms−1^{-1})

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Answer and worked solution

Official answer: C

For light the relativistic Doppler formula applies, with β=12\beta=\frac12:
f=f01+β1−β=103≈17.3 GHz.f=f_0\sqrt{\frac{1+\beta}{1-\beta}}=10\sqrt3\approx17.3\text{ GHz}.