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JEE Main 2017 · 2 Apr · Shift 1, Physics question 10

CpC_p and CvC_v are specific heats at constant pressure and constant volume respectively. It is observed that

Cp−Cv=aC_p-C_v=a for hydrogen gas

Cp−Cv=bC_p-C_v=b for nitrogen gas

The correct relation between a and b is :

Choose one option
Answer and worked solution

Official answer: C

Per unit mass, Cp−Cv=RMC_p-C_v=\dfrac RM. So a=R2a=\dfrac R2 for HX2\ce{H2} and b=R28b=\dfrac R{28} for NX2\ce{N2}, giving a=14ba=14b.