JEE Main 2017 · 2 Apr · Shift 1 · Mathematics Q89

← JEE Main 2017 · 2 Apr · Shift 1

MathematicsSingle correct+4 / -1Question 89 of 90

Let a vertical tower AB have its end A on the level ground. Let C be the mid-point of AB and P be a point on the ground such that AP = 2AB. If ∠BPC = β, then tan β is equal to :

\dfrac14

\dfrac29

\dfrac49

\dfrac67

Answer and worked solution

Official answer: B

With $AB=h$ and $AP=2h$ : $\tan\angle APB=\frac12$ and $\tan\angle APC=\frac14$ .
$\tan\beta=\frac{\frac12-\frac14}{1+\frac18}=\frac29.$

Topics:Heights and distances

← Previous question Next question →

JEE Main 2017 · 2 Apr · Shift 1, Mathematics question 89