JEE Main 2017 · 2 Apr · Shift 1 · Chemistry Q46

ChemistrySingle correct+4 / -1Question 46 of 90

The products obtained when chlorine gas reacts with cold and dilute aqueous NaOH are :

\ce{Cl-}

and

\ce{ClO-}

\ce{Cl-}

and

\ce{ClO2-}

\ce{ClO-}

and

\ce{ClO3-}

\ce{ClO2-}

and

\ce{ClO3-}

Answer and worked solution

Official answer: A

Cold, dilute alkali: $\ce{Cl2 + 2NaOH -> NaCl + NaOCl + H2O}$ , giving $\ce{Cl-}$ and $\ce{ClO-}$ . Hot, concentrated alkali gives chlorate instead.

JEE Main 2017 · 2 Apr · Shift 1, Chemistry question 46