JEE Main 2017 · 2 Apr · Shift 1 · Chemistry Q38

← JEE Main 2017 · 2 Apr · Shift 1

ChemistrySingle correct+4 / -1Question 38 of 90

The radius of the second Bohr orbit for hydrogen atom is :

(Planck's Const. $h=6.6262\times10^{-34}$ Js; mass of electron $=9.1091\times10^{-31}$ kg; charge of electron $e=1.60210\times10^{-19}$ C; permittivity of vacuum $\epsilon_0=8.854185\times10^{-12}$ kg $^{-1}$ m $^{-3}$ A $^2$ )

0.529 Å

2.12 Å

1.65 Å

4.76 Å

Answer and worked solution

Official answer: B

$r_n=0.529n^2$ Å, so $r_2=4\times0.529=2.12$ Å.

Topics:Bohr model

← Previous question Next question →

JEE Main 2017 · 2 Apr · Shift 1, Chemistry question 38