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← JEE Main 2016 · 10 Apr · Shift 1
PhysicsSingle correct+4 / -1Question 25 of 90

JEE Main 2016 · 10 Apr · Shift 1, Physics question 25

A particle of mass m is acted upon by a force F given by the empirical law F=Rt2v(t)F=\dfrac R{t^2}v(t). If this law is to be tested experimentally by observing the motion starting from rest, the best way is to plot :

Choose one option
Answer and worked solution

Official answer: D

mdvdt=Rt2vm\frac{dv}{dt}=\frac R{t^2}v gives ln⁡v=−Rmt+c\ln v=-\frac R{mt}+c, a straight line when log v is plotted against 1t\frac1t.