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← JEE Main 2016 · 10 Apr · Shift 1
MathematicsSingle correct+4 / -1Question 72 of 90

JEE Main 2016 · 10 Apr · Shift 1, Mathematics question 72

Let f(x)=sin⁡4x+cos⁡4xf(x)=\sin^4x+\cos^4x. Then f is an increasing function in the interval :

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Answer and worked solution

Official answer: B

f=1−12sin⁡22x=34+14cos⁡4xf=1-\frac12\sin^22x=\frac34+\frac14\cos4x, so f′=−sin⁡4x>0f'=-\sin4x>0 when 4x∈(π,2π)4x\in(\pi,2\pi): x∈(π4,π2)x\in\left(\frac\pi4,\frac\pi2\right).