JEE Main 2016 · 10 Apr · Shift 1 · Chemistry Q38

← JEE Main 2016 · 10 Apr · Shift 1

ChemistrySingle correct+4 / -1Question 38 of 90

Oxidation of succinate ion produces ethylene and carbon dioxide gases. On passing 0.2 Faraday electricity through an aqueous solution of potassium succinate, the total volume of gases (at both cathode and anode) at STP (1 atm and 273 K) is :

2.24 L

4.48 L

6.72 L

8.96 L

Answer and worked solution

Official answer: D

Kolbe electrolysis: at the anode $\ce{^-OOCCH2CH2COO^- -> C2H4 + 2CO2 + 2e-}$ ; at the cathode $\ce{2H2O + 2e- -> H2 + 2OH-}$ . With 0.2 F: 0.1 mol $\ce{C2H4}$ , 0.2 mol $\ce{CO2}$ and 0.1 mol $\ce{H2}$ , i.e. 0.4 mol = 8.96 L at STP.

Topics:Electrolysis and Faraday's laws

← Previous question Next question →

JEE Main 2016 · 10 Apr · Shift 1, Chemistry question 38