JEE Main 2016 · 10 Apr · Shift 1 · Chemistry Q32

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ChemistrySingle correct+4 / -1Question 32 of 90

Initially, the root mean square (rms) velocity of $\ce{N2}$ molecules at certain temperature is u. If this temperature is doubled and all the nitrogen molecules dissociate into nitrogen atoms, then the new rms velocity will be :

u/2

14u

Answer and worked solution

Official answer: B

$u_{rms}\propto\sqrt{\frac TM}$ . Doubling T and halving M multiplies it by $\sqrt4=2$ : 2u.

Topics:Kinetic theory of gases

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JEE Main 2016 · 10 Apr · Shift 1, Chemistry question 32