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← JEE Main 2016 · 9 Apr · Shift 1
PhysicsSingle correct+4 / -1Question 12 of 90

JEE Main 2016 · 9 Apr · Shift 1, Physics question 12

The potential (in volts) of a charge distribution is given by

V(z)=30−5z2V(z)=30-5z^2 for |z| ≤ 1 m

V(z) = 35 − 10 |z| for |z| ≥ 1 m.

V(z) does not depend on x and y. If this potential is generated by a constant charge per unit volume ρ0\rho_0 (in units of ϵ0\epsilon_0) which is spread over a certain region, then choose the correct statement.

Choose one option
Answer and worked solution

Official answer: A

From Gauss's law in one dimension, ρ=−ϵ0d2Vdz2\rho=-\epsilon_0\frac{d^2V}{dz^2}. For ∣z∣≤1|z|\le1, V′′=−10V''=-10, so ρ0=10ϵ0\rho_0=10\epsilon_0; outside, V is linear and ρ=0\rho=0.