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← JEE Main 2016 · 9 Apr · Shift 1
MathematicsSingle correct+4 / -1Question 89 of 90

JEE Main 2016 · 9 Apr · Shift 1, Mathematics question 89

If m and M are the minimum and the maximum values of 4+12sin⁡22x−2cos⁡4x4+\dfrac12\sin^22x-2\cos^4x, x∈Rx\in\mathbb R, then M − m is equal to :

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Answer and worked solution

Official answer: B

With c=cos⁡2xc=\cos^2x the expression is 4+2c−4c24+2c-4c^2 on [0, 1]: maximum 174\frac{17}4 at c=14c=\frac14, minimum 2 at c = 1. So M−m=94M-m=\frac94.