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← JEE Main 2016 · 9 Apr · Shift 1
MathematicsSingle correct+4 / -1Question 70 of 90

JEE Main 2016 · 9 Apr · Shift 1, Mathematics question 70

If lim⁡x→∞(1+ax−4x2)2x=e3\displaystyle\lim_{x\to\infty}\left(1+\frac ax-\frac4{x^2}\right)^{2x}=e^3, then 'a' is equal to :

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Answer and worked solution

Official answer: B

The limit is e2ae^{2a}, so 2a=32a=3 and a=32a=\frac32.

Topics:Limits