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← JEE Main 2016 · 9 Apr · Shift 1
ChemistrySingle correct+4 / -1Question 36 of 90

JEE Main 2016 · 9 Apr · Shift 1, Chemistry question 36

The solubility of NX2\ce{N2} in water at 300 K and 500 torr partial pressure is 0.01 g L−1^{-1}. The solubility (in g L−1^{-1}) at 750 torr partial pressure is :

Choose one option
Answer and worked solution

Official answer: B

By Henry's law solubility is proportional to pressure: 0.01×750500=0.0150.01\times\frac{750}{500}=0.015 g L⁻¹.