JEE Main 2016 · 3 Apr · Shift 1 · Physics Q30

← JEE Main 2016 · 3 Apr · Shift 1

PhysicsSingle correct+4 / -1Question 30 of 90

For a common emitter configuration, if α and β have their usual meanings, the incorrect relationship between α and β is :

\dfrac1\alpha=\dfrac1\beta+1

\alpha=\dfrac\beta{1-\beta}

\alpha=\dfrac\beta{1+\beta}

\alpha=\dfrac{\beta^2}{1+\beta^2}

Answer and worked solution

Official answer: B

$\alpha=\dfrac\beta{1+\beta}$ , equivalently $\dfrac1\alpha=\dfrac1\beta+1$ , so (1) and (3) are correct. (2) $\alpha=\dfrac\beta{1-\beta}$ is incorrect, and so is (4) $\alpha=\dfrac{\beta^2}{1+\beta^2}$ . The intended answer is (2); this derived key accepts both (2) and (4).

Topics:Transistors

← Previous question Next question →

JEE Main 2016 · 3 Apr · Shift 1, Physics question 30