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← JEE Main 2016 · 3 Apr · Shift 1
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JEE Main 2016 · 3 Apr · Shift 1, Physics question 26

A pipe open at both ends has a fundamental frequency ff in air. The pipe is dipped vertically in water so that half of it is in water. The fundamental frequency of the air column is now :

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Answer and worked solution

Official answer: D

Open pipe: f=v2Lf=\frac v{2L}. Half in water, it is a closed pipe of length L2\frac L2: f′=v4(L/2)=v2L=ff'=\frac v{4(L/2)}=\frac v{2L}=f.