JEE Main 2016 · 3 Apr · Shift 1 · Physics Q6

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PhysicsSingle correct+4 / -1Question 6 of 90

A satellite is revolving in a circular orbit at a height ' $h$ ' from the earth's surface (radius of earth R ; h << R). The minimum increase in its orbital velocity required, so that the satellite could escape from the earth's gravitational field, is close to : (Neglect the effect of atmosphere.)

\sqrt{2gR}

\sqrt{gR}

\sqrt{gR/2}

\sqrt{gR}\left(\sqrt2-1\right)

Answer and worked solution

Official answer: D

For $h\ll R$ , the orbital speed is $\sqrt{gR}$ and the escape speed is $\sqrt{2gR}$ . The increase needed is $\sqrt{gR}(\sqrt2-1)$ .

Topics:Satellites and orbital motion

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JEE Main 2016 · 3 Apr · Shift 1, Physics question 6