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JEE Main 2016 · 3 Apr · Shift 1, Physics question 1

A student measures the time period of 100 oscillations of a simple pendulum four times. The data set is 90 s, 91 s, 95 s and 92 s. If the minimum division in the measuring clock is 1 s, then the reported mean time should be :

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Answer and worked solution

Official answer: A

The mean is 90+91+95+924=92\frac{90+91+95+92}4=92 s. The deviations are 2, 1, 3 and 0 s, so the mean absolute error is 1.5 s. The clock reads only to 1 s, so the error is rounded up to a whole second: 92±292\pm2 s.