JEE Main 2016 · 3 Apr · Shift 1 · Chemistry Q56

ChemistrySingle correct+4 / -1Question 56 of 90

In the Hofmann bromamide degradation reaction, the number of moles of NaOH and $\ce{Br2}$ used per mole of amine produced are :

One mole of NaOH and one mole of

\ce{Br2}

Four moles of NaOH and two moles of

\ce{Br2}

Two moles of NaOH and two moles of

\ce{Br2}

Four moles of NaOH and one mole of

\ce{Br2}

Answer and worked solution

Official answer: D

$\ce{RCONH2 + Br2 + 4NaOH -> RNH2 + Na2CO3 + 2NaBr + 2H2O}$ : four moles of NaOH and one of $\ce{Br2}$ .

Topics:Amines

JEE Main 2016 · 3 Apr · Shift 1, Chemistry question 56