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JEE Main 2015 · 11 Apr · Shift 1, Physics question 15

An electric field E⃗=(25i^+30j^)\vec E=\left(25\hat i+30\hat j\right) NC−1^{-1} exists in a region of space. If the potential at the origin is taken to be zero then the potential at x=2x=2 m, y=2y=2 m is :

Choose one option
Answer and worked solution

Official answer: D

V=−∫E⃗⋅dr⃗=−(25×2+30×2)=−110 V.V=-\int\vec E\cdot d\vec r=-(25\times2+30\times2)=-110\text{ V}.
(The options print the unit as J.)

Topics:Electric potential
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