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JEE Main 2015 · 11 Apr · Shift 1, Physics question 11

Using equipartition of energy, the specific heat (in J kg−1^{-1} K−1^{-1}) of aluminium at room temperature can be estimated to be (atomic weight of aluminium = 27)

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Answer and worked solution

Official answer: C

Each atom has 3 degrees of freedom of vibration (kinetic and potential), so the molar heat capacity is 3R3R (Dulong-Petit).
c=3×8.3140.027≈925 J kg−1K−1.c=\frac{3\times8.314}{0.027}\approx925\text{ J kg}^{-1}\text{K}^{-1}.

Topics:Degrees of freedom and equipartitionCalorimetry and specific heat
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