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← JEE Main 2015 · 11 Apr · Shift 1
MathematicsSingle correct+4 / -1Question 75 of 90

JEE Main 2015 · 11 Apr · Shift 1, Mathematics question 75

Let f:R→Rf:\mathbb R\to\mathbb R be a function such that f(2−x)=f(2+x)f(2-x)=f(2+x) and f(4−x)=f(4+x)f(4-x)=f(4+x), for all x∈Rx\in\mathbb R and ∫02f(x) dx=5\displaystyle\int_0^2f(x)\,dx=5. Then the value of ∫1050f(x) dx\displaystyle\int_{10}^{50}f(x)\,dx is :

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Answer and worked solution

Official answer: B

Symmetry about x=2x=2 and x=4x=4 makes ff periodic with period 4. ∫04f=2×5=10\int_0^4f=2\times5=10, and [10,50][10,50] covers 10 periods: 100100.