JEE Main 2015 · 11 Apr · Shift 1 · Mathematics Q73

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MathematicsSingle correct+4 / -1Question 73 of 90

From the top of a 64 metres high tower, a stone is thrown upwards vertically with the velocity of 48 m/s. The greatest height (in metres) attained by the stone, assuming the value of the gravitational acceleration $g=32$ m/s $^2$ , is :

100

128

112

Answer and worked solution

Official answer: A

Extra rise $=\dfrac{48^2}{2\times32}=36$ m, so the greatest height above the ground is $64+36=100$ m.

Topics:Maxima and minima

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JEE Main 2015 · 11 Apr · Shift 1, Mathematics question 73