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← JEE Main 2015 · 11 Apr · Shift 1
ChemistrySingle correct+4 / -1Question 34 of 90

JEE Main 2015 · 11 Apr · Shift 1, Chemistry question 34

Molecule AB has a bond length of 1.617Å and a dipole moment of 0.38 D. The fractional charge on each atom (absolute magnitude) is : (e0=4.802×10−10e_0=4.802\times10^{-10} esu)

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Answer and worked solution

Official answer: B

δ=μed=0.38×10−184.802×10−10×1.617×10−8≈0.05.\delta=\frac\mu{ed}=\frac{0.38\times10^{-18}}{4.802\times10^{-10}\times1.617\times10^{-8}}\approx0.05.