JEE Main 2015 · 10 Apr · Shift 1 · Mathematics Q79

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MathematicsSingle correct+4 / -1Question 79 of 90

Let L be the line passing through the point P(1, 2) such that its intercepted segment between the co-ordinate axes is bisected at P. If $L_1$ is the line perpendicular to L and passing through the point (−2, 1), then the point of intersection of L and $L_1$ is :

\left(\dfrac45,\dfrac{12}5\right)

\left(\dfrac{11}{20},\dfrac{29}{10}\right)

\left(\dfrac3{10},\dfrac{17}5\right)

\left(\dfrac35,\dfrac{23}{10}\right)

Answer and worked solution

Official answer: A

L has intercepts 2 and 4: $2x+y=4$ . $L_1$ through $(-2,1)$ with slope $\frac12$ : $x-2y+4=0$ .

Solving: $x=\frac45$ , $y=\frac{12}5$ .

Topics:Equations of a line Angle between lines

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JEE Main 2015 · 10 Apr · Shift 1, Mathematics question 79