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JEE Main 2015 · 10 Apr · Shift 1, Mathematics question 76

The area (in square units) of the region bounded by the curves y+2x2=0y+2x^2=0 and y+3x2=1y+3x^2=1, is equal to :

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Answer and worked solution

Official answer: D

The curves y=−2x2y=-2x^2 and y=1−3x2y=1-3x^2 meet where x2=1x^2=1. Between them:
∫−11(1−x2) dx=43.\int_{-1}^1(1-x^2)\,dx=\frac43.

Topics:Area between curves
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