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← JEE Main 2015 · 10 Apr · Shift 1
MathematicsSingle correct+4 / -1Question 68 of 90

JEE Main 2015 · 10 Apr · Shift 1, Mathematics question 68

If the coefficients of the three successive terms in the binomial expansion of (1+x)n(1+x)^n are in the ratio 1 : 7 : 42, then the first of these terms in the expansion is :

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Answer and worked solution

Official answer: B

Let the terms be (nr−1),(nr),(nr+1)\binom n{r-1},\binom nr,\binom n{r+1}. Then n−r+1r=7\dfrac{n-r+1}r=7 and n−rr+1=6\dfrac{n-r}{r+1}=6, so n=8r−1=7r+6n=8r-1=7r+6, giving r=7r=7 and n=55n=55.

The first term is (556)x6=T7\binom{55}6x^6=T_7, the 7th term.