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← JEE Main 2015 · 10 Apr · Shift 1
MathematicsSingle correct+4 / -1Question 63 of 90

JEE Main 2015 · 10 Apr · Shift 1, Mathematics question 63

If 2+3i2+3i is one of the roots of the equation 2x3−9x2+kx−13=02x^3-9x^2+kx-13=0, k∈Rk\in\mathbb R, then the real root of this equation :

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Answer and worked solution

Official answer: B

The real coefficients mean 2−3i2-3i is also a root. The product of the roots is 132\frac{13}2, and (2+3i)(2−3i)=13(2+3i)(2-3i)=13, so the real root is 12\frac12.