JEE Main 2015 · 10 Apr · Shift 1 · Chemistry Q51

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ChemistrySingle correct+4 / -1Question 51 of 90

1.4 g of an organic compound was digested according to Kjeldahl's method and the ammonia evolved was absorbed in 60 mL of M/10 $\ce{H2SO4}$ solution. The excess sulphuric acid required 20 mL of M/10 NaOH solution for neutralization. The percentage of nitrogen in the compound is :

Answer and worked solution

Official answer: C

Acid taken: $60\times\frac1{10}\times2=12$ meq. Excess: $20\times\frac1{10}=2$ meq. So $\ce{NH3}$ is 10 meq.
That is 10 mmol N, i.e. 0.14 g:
$\%\text{N}=\frac{0.14}{1.4}\times100=10\%.$

Topics:Qualitative and quantitative analysis of organic compounds

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JEE Main 2015 · 10 Apr · Shift 1, Chemistry question 51