JEE Main 2015 · 10 Apr · Shift 1 · Chemistry Q47

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ChemistrySingle correct+4 / -1Question 47 of 90

An aqueous solution of a salt X turns blood red on treatment with $\ce{SCN-}$ and blue on treatment with $\ce{K4[Fe(CN)6]}$ . X also gives a positive chromyl chloride test. The salt X is :

\ce{CuCl2}

\ce{FeCl3}

\ce{Cu(NO3)2}

\ce{Fe(NO3)3}

Answer and worked solution

Official answer: B

Blood red with $\ce{SCN-}$ and Prussian blue with ferrocyanide mean $\ce{Fe^3+}$ . A positive chromyl chloride test means chloride. So X is $\ce{FeCl3}$ .

Topics:Cation analysis Anion analysis

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JEE Main 2015 · 10 Apr · Shift 1, Chemistry question 47