JEE Main 2015 · 10 Apr · Shift 1 · Chemistry Q37

← JEE Main 2015 · 10 Apr · Shift 1

ChemistrySingle correct+4 / -1Question 37 of 90

Gaseous $\ce{N2O4}$ dissociates into gaseous $\ce{NO2}$ according to the reaction
$\ce{N2O4(g) <=> 2NO2(g)}$
At 300 K and 1 atm pressure, the degree of dissociation of $\ce{N2O4}$ is 0.2. If one mole of $\ce{N2O4}$ gas is contained in a vessel, then the density of the equilibrium mixture is :

1.56 g/L

3.11 g/L

4.56 g/L

6.22 g/L

Answer and worked solution

Official answer: B

With $\alpha=0.2$ the mixture has 1.2 mol and the average molar mass is $\frac{92}{1.2}=76.7$ g/mol.
$\rho=\frac{PM}{RT}=\frac{1\times76.7}{0.0821\times300}\approx3.11\text{ g/L}.$

Topics:Law of mass action and Kc, Kp

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JEE Main 2015 · 10 Apr · Shift 1, Chemistry question 37