JEE Main 2015 · 10 Apr · Shift 1 · Chemistry Q31

← JEE Main 2015 · 10 Apr · Shift 1

ChemistrySingle correct+4 / -1Question 31 of 90

A sample of a hydrate of barium chloride weighing 61 g was heated until all the water of hydration is removed. The dried sample weighed 52 g. The formula of the hydrated salt is : (atomic mass, Ba = 137 amu, Cl = 35.5 amu)

\ce{BaCl2.H2O}

\ce{BaCl2.2H2O}

\ce{BaCl2.3H2O}

\ce{BaCl2.4H2O}

Answer and worked solution

Official answer: B

Water lost: 9 g $=0.5$ mol. Anhydrous $\ce{BaCl2}$ (208): 52 g $=0.25$ mol. The ratio is 1 : 2, so $\ce{BaCl2.2H2O}$ .

Topics:Mole concept

← Previous question Next question →

JEE Main 2015 · 10 Apr · Shift 1, Chemistry question 31