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← JEE Main 2015 · 4 Apr · Shift 1
PhysicsSingle correct+4 / -1Question 13 of 90

JEE Main 2015 · 4 Apr · Shift 1, Physics question 13

A train is moving on a straight track with speed 20 ms−1^{-1}. It is blowing its whistle at the frequency of 1000 Hz. The percentage change in the frequency heard by a person standing near the track as the train passes him is (speed of sound = 320 ms−1^{-1}) close to :

Choose one option
Answer and worked solution

Official answer: B

Approaching: f1=1000⋅320300=1066.7f_1=1000\cdot\frac{320}{300}=1066.7 Hz. Receding: f2=1000⋅320340=941.2f_2=1000\cdot\frac{320}{340}=941.2 Hz.
f1−f2f1=125.51066.7≈12%.\frac{f_1-f_2}{f_1}=\frac{125.5}{1066.7}\approx12\%.