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← JEE Main 2015 · 4 Apr · Shift 1
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JEE Main 2015 · 4 Apr · Shift 1, Physics question 9

Consider a spherical shell of radius R at temperature T. The black body radiation inside it can be considered as an ideal gas of photons with internal energy per unit volume u=UV∝T4u=\dfrac UV\propto T^4 and pressure p=13(UV)p=\dfrac13\left(\dfrac UV\right). If the shell now undergoes an adiabatic expansion the relation between T and R is :

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Answer and worked solution

Official answer: C

For the photon gas, p=u3p=\frac u3 and u∝T4u\propto T^4. In an adiabatic process dU=−p dVdU=-p\,dV with U=uVU=uV:
d(uV)=−u3dV  ⟹  V du=−43u dV  ⟹  u∝V−4/3.d(uV)=-\frac u3dV\implies V\,du=-\frac43u\,dV\implies u\propto V^{-4/3}.
So T4∝V−4/3T^4\propto V^{-4/3}, T∝V−1/3∝1RT\propto V^{-1/3}\propto\dfrac1R.