JEE Main 2015 · 4 Apr · Shift 1 · Physics Q5

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PhysicsSingle correct+4 / -1Question 5 of 90

Distance of the centre of mass of a solid uniform cone from its vertex is $z_0$ . If the radius of its base is R and its height is h then $z_0$ is equal to :

\dfrac{h^2}{4R}

\dfrac{3h}4

\dfrac{5h}8

\dfrac{3h^2}{8R}

Answer and worked solution

Official answer: B

For a solid cone the centre of mass is $\frac h4$ above the base, so $\dfrac{3h}4$ from the vertex.

Topics:Centre of mass

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JEE Main 2015 · 4 Apr · Shift 1, Physics question 5