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← JEE Main 2015 · 4 Apr · Shift 1
MathematicsSingle correct+4 / -1Question 82 of 90

JEE Main 2015 · 4 Apr · Shift 1, Mathematics question 82

Let O be the vertex and Q be any point on the parabola, x2=8yx^2=8y. If the point P divides the line segment OQ internally in the ratio 1 : 3, then the locus of P is :

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Answer and worked solution

Official answer: D

Q=(4t,2t2)Q=(4t,2t^2) and P=14Q=(t,t22)P=\frac14Q=\left(t,\frac{t^2}2\right), so the locus is x2=2yx^2=2y.