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← JEE Main 2015 · 4 Apr · Shift 1
ChemistrySingle correct+4 / -1Question 56 of 90

JEE Main 2015 · 4 Apr · Shift 1, Chemistry question 56

In the reaction
p-CHX3CX6HX4NHX2→0−5X∘CNaNOX2/HClD→ΔCuCN/KCNE+NX2p\text{-}\ce{CH3C6H4NH2 ->[NaNO2/HCl][0-5^\circ C] D ->[CuCN/KCN][\Delta] E + N2}
the product E is :

p-Toluidine (NH₂ and CH₃ para on a benzene ring) → NaNO₂/HCl, 0-5 °C → D → CuCN/KCN, Δ → E + N₂.
Choose one option
Answer and worked solution

Official answer: C

p-Toluidine is diazotised to the diazonium salt (D). CuCN/KCN (Sandmeyer) replaces NX2X+\ce{N2+} by CN, giving p-tolunitrile, structure (3).