JEE Main 2015 · 4 Apr · Shift 1 · Chemistry Q51

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In Carius method of estimation of halogens, 250 mg of an organic compound gave 141 mg of AgBr. The percentage of bromine in the compound is : (at. mass Ag = 108; Br = 80)

Answer and worked solution

Official answer: A

Br in 141 mg AgBr: $141\times\frac{80}{188}=60$ mg.
$\%\text{Br}=\frac{60}{250}\times100=24\%.$

Topics:Qualitative and quantitative analysis of organic compounds

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JEE Main 2015 · 4 Apr · Shift 1, Chemistry question 51