JEE Main 2015 · 4 Apr · Shift 1 · Chemistry Q49

ChemistrySingle correct+4 / -1Question 49 of 90

The color of $\ce{KMnO4}$ is due to :

M → L charge transfer transition

d − d transition

L → M charge transfer transition

σ − σ* transition

Answer and worked solution

Official answer: C

Mn(VII) in $\ce{MnO4-}$ is $d^0$ , so there are no d-d transitions. The intense purple colour is from ligand-to-metal charge transfer, O → Mn.

JEE Main 2015 · 4 Apr · Shift 1, Chemistry question 49