JEE Main 2015 · 4 Apr · Shift 1 · Chemistry Q31

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The molecular formula of a commercial resin used for exchanging ions in water softening is $\ce{C8H7SO3Na}$ (Mol. wt. 206). What would be the maximum uptake of $\ce{Ca^2+}$ ions by the resin when expressed in mole per gram resin ?

\dfrac1{103}

\dfrac1{206}

\dfrac2{309}

\dfrac1{412}

Answer and worked solution

Official answer: D

Each $\ce{Ca^2+}$ replaces two $\ce{Na+}$ , so it needs two resin units, $2\times206=412$ g. The maximum uptake is $\dfrac1{412}$ mol per gram.

Topics:Mole concept

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JEE Main 2015 · 4 Apr · Shift 1, Chemistry question 31