JEE Main 2014 · 19 Apr · Shift 1 · Physics Q18

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Four bulbs $B_1$ , $B_2$ , $B_3$ and $B_4$ of 100 W each are connected to 220 V main as shown in the figure. The reading in an ideal ammeter will be :

The 220 V mains feeds four bulbs B₁-B₄ connected in parallel between a top and a bottom wire; the ammeter is in the bottom wire between B₁ and B₂, so it carries the current of bulbs B₂, B₃ and B₄.

0.45 A

0.90 A

1.35 A

1.80 A

Answer and worked solution

Official answer: C

All four bulbs are in parallel across 220 V, each drawing $\frac{100}{220}=0.4545$ A. The ammeter sits in the line feeding three of them:
$I=3\times0.4545\approx1.35\text{ A}.$

Topics:Electrical power and heating Series and parallel resistors

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JEE Main 2014 · 19 Apr · Shift 1, Physics question 18