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← JEE Main 2014 · 19 Apr · Shift 1
PhysicsSingle correct+4 / -1Question 6 of 90

JEE Main 2014 · 19 Apr · Shift 1, Physics question 6

A ball of mass 160 g is thrown up at an angle of 60° to the horizontal at a speed of 10 ms−1^{-1}. The angular momentum of the ball at the highest point of the trajectory with respect to the point from which the ball is thrown is nearly (g=10g=10 ms−2^{-2})

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Answer and worked solution

Official answer: B

At the top v=10cos⁡60∘=5v=10\cos60^\circ=5 m/s, horizontal, at height H=(10sin⁡60∘)22g=3.75H=\dfrac{(10\sin60^\circ)^2}{2g}=3.75 m.
L=mvH=0.16×5×3.75=3.0 kg m2/s.L=mvH=0.16\times5\times3.75=3.0\text{ kg m}^2\text{/s}.