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← JEE Main 2014 · 19 Apr · Shift 1
MathematicsSingle correct+4 / -1Question 86 of 90

JEE Main 2014 · 19 Apr · Shift 1, Mathematics question 86

Let A and E be any two events with positive probabilities :

Statement - 1 : P(E/A)≥P(A/E)P(E)P(E/A)\ge P(A/E)P(E)

Statement - 2 : P(A/E)≥P(A∩E)P(A/E)\ge P(A\cap E).

Choose one option
Answer and worked solution

Official answer: A

  • Statement 1: P(A/E)P(E)=P(A∩E)P(A/E)P(E)=P(A\cap E) and P(E/A)=P(A∩E)P(A)≥P(A∩E)P(E/A)=\dfrac{P(A\cap E)}{P(A)}\ge P(A\cap E). True.
  • Statement 2: P(A/E)=P(A∩E)P(E)≥P(A∩E)P(A/E)=\dfrac{P(A\cap E)}{P(E)}\ge P(A\cap E). True.

Both are true.