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← JEE Main 2014 · 19 Apr · Shift 1
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JEE Main 2014 · 19 Apr · Shift 1, Mathematics question 68

The number of terms in an A.P. is even; the sum of the odd terms in it is 24 and that the even terms is 30. If the last term exceeds the first term by 101210\frac12, then the number of terms in the A.P. is :

Choose one option
Answer and worked solution

Official answer: B

With 2k2k terms, Seven−Sodd=kd=6S_{even}-S_{odd}=kd=6. Also (2k−1)d=212(2k-1)d=\frac{21}2. Dividing: 2k−1k=74\frac{2k-1}k=\frac74, so k=4k=4: 8 terms.